→ ntust661 :其他都是湊成定義囉!! 11/06 19:20
※ 引述《iamsheep (??)》之銘言：
: 1.Suppose f'(1) = 1. Find the limit lim [f(x^2)-f(1)]/(x+1)
: x->-1
2
f( x ) - f(1)
lim ───────── (x - 1)
x→-1 x^2 - 1
2
= lim f'(x ) (x-1)
x→-1
= -2
: ans:-2
: 2.Suppose f(1) = -1 and f'(1) = 2.
: Find the limit lim [x^2f(1)-f(x^2)]/(x-1)
: x->1
: ans:-6
: 3.given that f(2) = 1 and f'(2) = 0,Find the limit
: lim [xf(2)-2f(x)]/(x-2)
: x->2
: ans:1
: 請問怎麼解?
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※ 編輯: ntust661 來自: 218.161.123.230 (11/06 19:19)