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※ 引述《paggei (XD)》之銘言: : (1) Prove that a group that has only a finite number of subgroups : must be finite. : (2) 舉一個無窮乘法循環群的例子 : (3) G is group, H is a subgroup of G : Prove that the number of all distinct right cosets of H in G is equal to : the number of all distinct left cosets of H in C : 即使考完了還是不會(炸) : 想請問這幾題如何做呢@@ (1)Let G be a group a屬於G and let <a> be the cyclic subgroup generated by a. Consider U <a> = G a屬於G since G has only finite number subgroups and since the set of all cyclic subgroups is a subset of all subgroups, we have there are only finite number cyclic subgroups says <a_1>,<a_2>, <a_3>....<a_m>. Then G = U <a_i> i從一到m claim that for each i , <a_i> is finite. If <a_i> is not finite, then <a_i ^k> for k屬於N are cyclic subgroups of <a_i>, which is infinite many,and are also subgroups of G This contradicting to G has only finite number subgroups. Hence,G is finite union of finite set is also finite. -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.113.69.88
peace0907 :第三題的話 define function φ(gH) = Hg g屬於G 11/09 16:55
peace0907 :check 1-1 and onto 11/09 16:55
peace0907 :不好意思 應該是 φ(gH) = Hg^-1 11/09 17:11
t1552050027 :謝謝你Q____Q 我想好久了 11/09 22:57