→ a88241050 :三角代換 11/12 19:29
→ t1552050027 :let x=tany 11/12 19:30
推 mvpnashmvp :答案應該是arctanx+c 11/12 19:32
→ doublewhi :它有個平方耶? arctanx = =? 11/12 19:33
推 j0958322080 :S(cosx)^2 dx 11/12 19:34
推 goshfju :x=tanθ -> 1+x^2=sec^2θ , dx=sec^2θdθ 11/12 19:36
→ lineagenew :懂了!!! 感謝樓上諸位的提示~~^^ 11/12 19:38
推 suhorng :1/(1+x^2)^2 = 1/(1+x^2) - x^2/(1+x^2) 11/13 19:29
→ suhorng :前者arctan, 後者分部積分:0.5x * 2x/(1+x^2)dx 11/13 19:30