推 robert780612:謝謝，答案是發散才對 02/02 16:07
※ 引述《robert780612 (.....)》之銘言：
: lim (log2+log3+...+logn)/n
: n->∞
n > 1
n n
Σlog(k)≧Σlog(k) = log(n) + log(n-1) + ... + log[n/2]
k=1 k=[n/2]
n
≧Σ log[n/2]
k=[n/2]
≧(n/2)log[n/2]
=> (log1 + log2 + log3 + ... + logn)/n ≧ 1/2 log[n/2]
: 我覺得答案應該是0，可是不知道該怎麼下手
--
※ 發信站: 批踢踢實業坊(ptt.cc)
◆ From: 59.115.150.167