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※ 引述《silentsecret ()》之銘言: : 若A、B為n*n實矩陣,AB=BA : 證明A、B有一共同的eigenvector : 請問大家了! over C, there exists some k that is an eigenvalue of A Let V=ker(A-kI) AB=BA => V is stable under B. So, as a morphism, we can consider the restriction B|V Again, there exists an eigenvector (in V) for B|V. Then we are done. PS.This implies that if A has n different eigenvalues,then B is diagonalizable. -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 76.94.119.209 ※ 編輯: Sfly 來自: 76.94.119.209 (02/15 16:32)
jack0711 :如果A.B可對角化,但存在相同λ的話敘述也會成立 02/15 16:33
hjmeric :請問這裡的stable是什麼意思? 02/15 16:35
jack0711 :提供名師的證明:http://ppt.cc/hczy 02/15 16:39
※ 編輯: Sfly 來自: 76.94.119.209 (02/15 16:41)
Sfly :stable: B maps V into V. 02/15 16:44
jacky7987 :B-invariant 02/15 16:48
hjmeric :謝謝! 02/15 16:49