[線代] A*A的分解

[bjiyxo (若自礌)]

find a matrix B such that B*B=[4 0 0; 0 1 i; 0 -i 1]
where the B* is the transpose of a conjugate matrix B

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◆ From: 140.113.139.168
推 ww770829    :么正對角化
→ bjiyxo      :可不可以詳細說一下怎麼算?
推 powerkshs   :B*B=QDQ^-1＝QD^(1/2)Q^(-1)QD^(1/2)Q^-1
→ bjiyxo      :喔喔我懂了~~ 謝謝:)