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※ 引述《claudina (claudina)》之銘言: : Let S be the surface parametrized by r(θ,z)=3sin2θi+6sin^2θj+zk where : 0<=θ<=π. Which of the following is equivalent to the surface differential : d∂? 好吧..還是我回你了 剛好我也要考台聯大 i j k i j k                dx/dθ dy/dθ dz/dθ 6cos2θ 12sinθcosθ 0 ∣            ∣ = |            | dx/dz dy/dz dz/dz 0 0 1 = | i6sin2θ-j6cos2θ | 取絕對值答案= 6dθdz -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 122.118.50.64
claudina : 05/27 19:08