[微積] 函數微分

[silentchaos (眷戀)]

set
        3          x=0

f(x)=   -x^2+3x+3  0<x<1

        x+4        1=<x=<2




f'(x)=  -2x+3  0<x<1

        1      1<x<2

Just want to ask if f'(1-)=f'(1+)=f'(1)

or there is no definition on f'(1) ?

THX~

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→ bineapple   :f'(1)=1  just using the definition of f'(1)
→ silentchaos :thx