看板 Math 關於我們 聯絡資訊
※ 引述《LSCAT (秘密客)》之銘言: : Suppose that X is a continuous random variable with density f and cdf F. : We say that X has tail-index a if : limx->∞ x^a.[1 - F(x)] = A; : for some positive, finite number A. : Prove that X has tail-index a if and only if 上面這個應該是limx->∞ x^a.[1 - F(x)] = A ? : limx->∞ x^a+1.f(x) = aA: : 想請教高人一下!^^ Thanks! pf: 首先 a必>0, 如果a<=0 則因為 lim(1-F(x)) -> 0 則A不可能為正數 (=>) 以下極限為 x->∞ A = lim x^a.[1 - F(x)] = lim { x^(a+1).[1 - F(x)] / x } 注意到上式 分子分母 -> ∞ 用L'Hospital = lim { [(a+1)x^a.[1 - F(x)] + x^(a+1)*(-f(x)) ] / 1 } = (a+1)A - lim { x^a+1.f(x) } so lim { x^a+1.f(x) } = aA (<=) lim {x^a *[1-F(x)]} = lim { [1-F(x)] / [1/x^a] } L' = lim { -f(x) / [-a* 1/x^(a+1)] } = (1/a) lim x^(a+1)*f(x) = A -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 123.193.50.247
yhliu :一個疑問: 在 tail-index a 的條件下, 如何證明 09/18 22:30
yhliu :lim x^{a+1} f(x) 存在? 09/18 22:30