Re: [線代] 有人可以解一下這一題線性方程嗎?(22變數)

[bugmens (今天天氣好)]

※ 引述《utomaya (烏托馬雅)》之銘言：
: 誰手上有Mathematica的
: 可以解一下這一題線性方程嗎?
: 要最簡分數的解
: 22個變數(A~U)
: 請注意一下 其中有一個是-A-2B-3C-4D+36"O"=0(是36歐 不是三百六)
: 500P幣酬謝
: 35A-2M-3N-4O-5P-6Q-5R-4S-3T-2U-V=0,
: -A+34B-3N-4O-5P-6Q-5R-4S-3T-2U-V=0,
: -A-2B+33C-4O-5P-6Q-5R-4S-3T-2U-V=0,
: -A-2B-3C+32D-5P-6Q-5R-4S-3T-2U-V=0,
: -A-2B-3C-4D+31E-6Q-5R-4S-3T-2U-V=0,
: -A-2B-3C-4D-5E+36F-5R-4S-3T-2U-V-6=0,
: -A-2B-3C-4D-5E-6F+31G-4S-3T-2U-V=0,
: -A-2B-3C-4D-5E-6F-5G+32H-3T-2U-V=0,
: -A-2B-3C-4D-5E-6F-5G-4H+33I-2U-V=0,
: -A-2B-3C-4D-5E-6F-5G-4H-3I+34J-V=0,
: -A-2B-3C-4D-5E-6F-5G-4H-3I-2J+35K=0,
: -A+36L=0,
: -A-2B+36M=0,
: -A-2B-3C+36N=0,
: -A-2B-3C-4D+36O=0,
: -A-2B-3C-4D-5E+36P=0,
: -A-2B-3C-4D-5E+36Q-6=0,
: -A-2B-3C-4D-5E-6F-5G+36R=0,
: -A-2B-3C-4D-5E-6F-5G-4H+36S=0,
: -A-2B-3C-4D-5E-6F-5G-4H-3I+36T=0,
: -A-2B-3C-4D-5E-6F-5G-4H-3I-2J+36U=0,
: -A-2B-3C-4D-5E-6F-5G-4H-3I-2J-K+36V=0,
http://i.imgur.com/tPWxR.gif
solve(%,[A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T,U,V]);
[[A=115502118987577/927345579814224,
  B=243419775195317/1854691159628448,
  C=21812760880537/154557596635704,
  D=880527134317/5724355430952,
  E=80364927451/477029619246,
  F=94406724113/318019746164,
  G=207398933487/1113069111574,
  H=211141113777/1113069111574,
  I=106296174774/556534555787,
  J=106460465616/556534555787,
  K=106460465616/556534555787,
  L=115502118987577/33384440873312064,
  M=19940105232383/1854691159628448,
  N=579900918235/25759599439284,
  O=680109656929/17173066292856,
  P=15026865197/238514809623,
  Q=36519555645/159009873082,
  R=77000683707/556534555787,
  S=177461491167/1113069111574,
  T=97588760148/556534555787,
  U=14786175780/79504936541,
  V=106460465616/556534555787
]]

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