推 dewgrw :感謝!^^" 11/01 22:52
※ 引述《dewgrw (狗爸)》之銘言:
: a f(x)
: 令 I = ∫ -------------- dx ,證明 I = a/2
: 0 f(x)+f(a-x)
a f(x) a [ -f(a-x) ]
I = ∫ -------------- dx = ∫ [-------------- + 1 ] dx
0 f(x) + f(a-x) 0 [ f(x) + f(a-x) ]
0 f(u)
= ∫ -------------- du + a = -I + a ( Let a-x = u. )
a f(u) + f(a-u)
2I = a
I = a/2
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