Re: [微積] 反三角函數的微分

[zxcv0011 (銀月)]

(sinx+cosx)/(sinx-cosx) = (sinx+cosx)^2/(sinx^2-cosx^2) = (1+sin2x)/-cos2x
= -tan2x-sec2x

y’(x) = (-1/(1+(-tan2x-sec2x)^2))*(-2sec2x^2-2tan2xsec2x)
y’(0) = (-1/2)*(-2) = 1

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※ 編輯: zxcv0011        來自: 140.112.187.116      (11/07 12:59)
推 peterkot    :感謝大大