※ 引述《wsx02 ()》之銘言：
: http://ppt.cc/gIRY
: 請問最底下的 solve the system for this value of k and determine the solution
: for which x^2 + y^2 + z^2 has at least value
: 請問這個要怎麼算?
: 謝謝
Let detA = 0, then k = -3 or 2.
There is no solution for the system as k = -3.
When k = 2, the system has more than one solution.
t 3 3 0
Define B = AA = [3 17 14] , thus
0 14 14
4/21
[1/7 ] is one solution of the system w.r.t the matrix B.
0
t 4/21
Hence, A [1/7 ] is the minimal solution of the system for the matrix A
0
which x^2+y^2+z^2 has at least value when k = 2.
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～by Jackary P.～
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