推 wsx02 :謝謝 11/10 23:01
※ 引述《Annihilator (> No LOVE (%))》之銘言：
: ※ 引述《wsx02 ()》之銘言：
: : http://ppt.cc/gIRY
: : 請問最底下的 solve the system for this value of k and determine the solution
: : for which x^2 + y^2 + z^2 has at least value
: : 請問這個要怎麼算?
: : 謝謝
: Let detA = 0, then k = -3 or 2.
: There is no solution for the system as k = -3.
: When k = 2, the system has more than one solution.
1 1 -1 | 1
透過 [2 3 2 | 3] 做高斯消去法
1 2 3 | 2 0 5
<[1],[-4]>
0 5 0 0 1 5
可得解 [1] + z[-4] , 則 [1] - ----------[-4]
0 1 0 42 1
即為所求(會跟下面算出來的結果一致)
: t 3 3 0
: Define B = AA = [3 17 14] , thus
: 0 14 14
: 4/21
: [1/7 ] is one solution of the system w.r.t the matrix B.
: 0
: t 4/21
: Hence, A [1/7 ] is the minimal solution of the system for the matrix A
: 0
: which x^2+y^2+z^2 has at least value when k = 2.
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