推 bn51401 :f(1+i) = a+bi 則共軛的f(1-i)的為 a-bi 合為整數 01/22 21:12
→ a88241050 :(1+i)^n+(1-i)^n必為實數 01/22 21:16
→ jashbala :謝謝h大 我看到的解釋跟您寫的一樣 但不知道為什麼 01/22 22:40
→ jashbala :共軛f(1-i)會是a-bi 01/22 22:41
推 suhorng :f(\bar z) = \bar f(z) 01/22 22:48
→ suhorng :because \bar{zw} = \bar{z}\bar{w} 01/22 22:49
→ suhorng :\bar{z+w}=\bar{z}+\bar{w}, 且f實係數 01/22 22:49
→ jashbala :謝謝s大 01/23 01:58