[微積] 有點小難的

[kelvin811 (sheila)]

work through the following sequences of substitutions for
∫√〔1+sin^2(x-1)〕 sin(x-1) cos(x-1) dx

Q1. u=x-1, following by v=sin(u), then by w=1+v^2
Q2. u=sin(x-1), following by v=sin(u), then by v=1+u^2
Q3. u=1+〔sin^2 (x-1)〕

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→ suhorng     :步驟不是都給了@@
→ kelvin811   :>"<因為不知道該怎麼做
→ geine956    :Q2抄錯了吧??另外，大推一樓，明明都給好步驟啦
→ geine956    :看看課本範例，照樣變數變換，注意du跟dx怎麼換就好
→ Rasin       :看就知道平時不燒香..
→ kelvin811   :不是平時不燒香...而是我已經畢業很久了!
→ kelvin811   :現在突然被問!!線在哪位善心人士幫我一下>"<
→ kittor      :cos(x-1)dx=dsin(x-1),sin(x-1)dsin(x-1)=(1/2)dsin^
→ kittor      :2(x-1)=(1/2)d(1+sin^2(x-1))，再用變數變換