→ hongo1120 :謝謝 03/13 15:53
y-2xy-y^2=0 ... (1)
x-x^2-2xy=0 ... (2)
(2)-(1)
(x-y) - (x^2-y^2) = 0 = (x-y)(1-x-y)=0
(i) x-y = 0 => y=x 代入(2)
x-x^2-2x^2 = 0 => x = y = 0 v 1/3
(ii) 1-x-y = 0 => y=1-x 代入(2)
x-x^2-2x(1-x) = 0 解得 x = 0 v 1
(x,y) = (0,0) (0,1) (1/3,1/3) (1,0)
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