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y-2xy-y^2=0 ... (1) x-x^2-2xy=0 ... (2) (2)-(1) (x-y) - (x^2-y^2) = 0 = (x-y)(1-x-y)=0 (i) x-y = 0 => y=x 代入(2) x-x^2-2x^2 = 0 => x = y = 0 v 1/3 (ii) 1-x-y = 0 => y=1-x 代入(2) x-x^2-2x(1-x) = 0 解得 x = 0 v 1 (x,y) = (0,0) (0,1) (1/3,1/3) (1,0) -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 180.176.110.251
hongo1120 :謝謝 03/13 15:53