推 mike790158 :多謝解答! 06/19 22:11
※ 引述《mike790158 (~這麼晚還沒睡~)》之銘言：
: 請問這題如何計算?
: ∫{(2z-1)/(4z-1)} dz
2z-1 0.5(4z-1)-0.5 1
∫──── dz = ∫─────── dz = 0.5∫(1- ───)dz
4z-1 4z-1 4z-1
= 0.5z -0.125ln│4z-1│ +c
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