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※ 引述《wa007123456 (大笨羊)》之銘言: : 大家好! 以下是題目 : ============================================== : a為101^x+x-5=0之一根 b為log<101>(x)+x-5=0 之一根 : 求a+b (log<x>表示以x為底數) : ============================================= : 感謝回答>< denote f(x) = 101^x denote f inverse as f^ a = f^f(a) = f^(-a+5) denote u = -a + 5 -u + 5 = f^(u) f^(b) = -b + 5 however, f^(x), x are both strictly increasing hence, f^(x) + x is strictly increasing then f^(x) + x = 5 has a unique solution then u = b then - a + 5 = b a + b = 5 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 123.194.224.241
wa007123456 :謝謝你 可是我看不懂 囧 08/14 11:51
wa007123456 :我只看到嚴格遞增... 08/14 11:52
wa007123456 :所以其實這兩個式子都只有一個解囉? 08/14 11:53
wa007123456 :inverse 是指反函數嗎? 08/14 11:53