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※ 引述《hmichellesa (mim)》之銘言: : 1.show that the differential equation has a regular singular point about z=0 z^2y"+zy'+(z^2-v^2)y=0 : 謝謝各位大大幫忙X-( z^2 = 0 => z = 0 (z-0)z ------- = 1 z^2 (z-0)^2 (z^2 - v^2) ------------------- = z^2 - v^2 當在z=0處 nonsingular z^2 所以z = 0是 regular singular point -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 128.220.144.133
hmichellesa :謝謝h大幫忙.....(貴人) 08/30 17:14
Heaviside :偷推一下h大! 08/30 23:19