推 mitsuyo :感謝 300p 09/18 12:32
※ 引述《mitsuyo (光世)》之銘言:
: http://imgur.com/qBJM1MM
: dC/dx=0 (C對x偏微分為0)
d(uE)/dx + CdE/dx = (-3/2)Edu/dx
=> (5/2)Edu/dx + udE/dx + CdE/dx = 0
=> (5/2)Edu/dx = -(u+C)dE/dx
=> (5/2)du/(u+C) = -dE/E
=> (5/2)ln(u+C) = -lnE + A 其中 dA/dx = 0偏微分
=> (u+C)^(5/2) = (1/E)exp(A) = B/E 其中 dB/dx = 0 偏微分
=> E = B/(u+C)^(5/2)
: 這題這樣平衡對嗎?拜託各位神人解惑.謝謝^^.
: ~
: 微薄 300p酬謝 ..謝謝
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