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f is continuous <=> preimage of an open set is open <=> preimage of a closed set is closed choose any subinterval J with irrational end points, then f^{-1}(J) is open and closed, so it is either empty or R. So obviously f is a constant. -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.247.0.119 ※ 編輯: JASS0213 來自: 140.247.0.119 (09/30 05:13)
JASS0213 :In this case your domain can be any connected 09/30 11:27
JASS0213 :topological space 09/30 11:28
ssss50201 :謝謝您!! 09/30 20:39