推 stman :所以可以直接微分? 11/09 10:13
→ suhorng :f(t) continuous => ∫[c,x] f(t)dt differentiable 11/09 10:43
※ 引述《stman (小強)》之銘言：
: If f is continuous function such that
: x x x 2
: ∫ f(t) dt = xe -∫ t f(t)dt
: 0 0
: for all x, find an explicit formula fo f(x).
f(x) = e^x + xe^x - [x^2 f(x)]
f(x) = (1+x)exp(x)/(1+x^2)
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