→ yueayase :不就sigma(1~n)(1/(a^(2^n)-b^(2^n)))? 12/04 00:22
→ ideaptt :1/(a-b)+1/(a^2-b^2)=[(a^2+b^2)+a+b+1]/(a^4-b^4) 12/05 01:32
→ ideaptt :correction 12/05 01:33
→ ideaptt :1/(a-b)+1/(a^2-b^2)=[(a^2+b^2)+a+b+1]/(a^2-b^2) 12/05 01:34
→ ideaptt :above+1/(a^4-b^4)=... 12/05 01:36
→ ideaptt :...=[(a^4+b^4)+a^2+b^2+a+b+1]/(a^4-b^4) 12/05 01:37
→ ideaptt :see the rule? move the dominator's part to the 12/05 01:39
→ ideaptt :numerator and the numerator could be separated 12/05 01:39
→ ideaptt :into the geometry seq. of a,b respectively. so 12/05 01:40
→ ideaptt :the numerator could expressed as a formula of n 12/05 01:41
→ ideaptt :and the dominator is simple. 12/05 01:41