→ wayn2008 :(3+11)/2=7 │x-7│=4 => │-1/7*x+1│=4/7 03/07 00:35
→ binbinthink :|ax+1|=b,同除以a,|x+1/a|=b/|a| 03/08 11:50
→ binbinthink :|x-(-1/a)|=b/|a|, 03/08 11:51
→ binbinthink :3,11代入得,|3-(-1/a)|=b/|a|,|11-(-1/a)|=b/|a| 03/08 11:52
→ binbinthink :比較兩式得知3到(-1/a)的距離與11到(-1/a)相等 03/08 11:53
→ binbinthink :故(-1/a)=(3,11中點7),得a=-1/7 03/08 11:54
→ binbinthink :同理比較兩式得距離為 b/|a|=4,a代入得b=4/7 03/08 11:55
推 wanderwander:分別平方 03/09 01:33
→ wanderwander:(3a+1)^2=(11a+1)^2=b^2 03/09 01:37
→ wanderwander:求得a後再帶入得b 03/09 01:38
→ wanderwander:(a,b)=(0,1)or(-1/7,4/7) 03/09 01:41
推 binbinthink :個人覺得(a,b)=(0,1)代入|0x+1|=1,x=3or11是有問題的 03/10 16:43
→ binbinthink :(0,1)不太適合當答案 03/10 16:43