→ bjiyxo :該括號的要括啊= = 03/24 18:23
→ bjiyxo :如果你是4/(2+sin^2(x)),我會建議把它畫成 03/24 18:34
→ bjiyxo :4sec^2(x)/(2+3tan^2(x)),這樣令u=tanx會非常好做 03/24 18:35
→ tetsukaii :XXX謝謝 03/24 19:18
→ tetsukaii :但令u=tanx還是解不出來耶 03/24 20:57
→ Eliphalet :4sec^2(x)/(2+3tan^2(x))dx=4dtan(x)/(2+3tan^2(x)) 03/24 21:08