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※ 引述《opagainop (12345)》之銘言: : A = (1/2)(3/4)(5/6)(7/8)........(99/100) : B = (2/3)(4/5)(6/7)(8/9)........(100/101) : C = 1/10 : D = 1/11 : 試求 A,C (比大小) : B,D (比大小) : 感謝各位高手解題 ^^ 首先,因為1/2 < 2/3 , 3/4 < 4/5 ....99/100 < 100/101 顯然 A < B 故 A^2 < AB = 1/101 → A < 1/√101 < 1/√100 = 1/10 = C 且 1/101 = AB < B^2 → B > 1/√101 > 1/√121 = 1/11 = D -- ※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 1.162.103.48 ※ 文章網址: http://www.ptt.cc/bbs/Math/M.1411906714.A.16C.html
opagainop : 感謝 10/04 19:35