看板 NTU-Exam 關於我們 聯絡資訊
課程名稱︰ 自動機與形式語言 課程性質︰ 資工系必修 課程教師︰ 林智仁 開課學院: 電資學院 開課系所︰ 資工系 考試日期(年月日)︰ 2008.10.16 考試時限(分鐘): 90分鐘 是否需發放獎勵金: 是 (如未明確表示,則不予發放) 試題 : Please give details of your calculation. A direct answer withour explanation is not counted. Your answers must be in English. Please carefully read problem statements. 1.(20%) (a) In proving that (√2) is an irrational number, we used the following property: 2 (n) is even → n is even. (1) Formally prove (1). y (b) Do two irrational numbers x, y exist such that x is a rational number? Please prove your answer (yes or no). (√2) Hint: consider (√2) . 2.(25%) Assume Σ={a,b}. Consider a regular language A with the following NFA diagram: → a↑↓ ┌─┐ │q1│ └─┘↖ ↗ ↘ ↖ b a↗ ↘ ↖ ↗ a↘ ↖ ↗ ↘ ↖ ╔═╗ a ┌─┐ →║q0║→→→→→→→→│q2│ ╚═╝←←←←←←←←└─┘ ε Give an NFA diagram which accepts the complement of A: _ A = {w | w dose not belong to A}. You don't need to give the formal five-tuple definition. 3.(15%) Given a regular language A and assume it is represented by (Q1,Σ,δ1,q1,F1). Let + A = {(W1)...(Wk) | k is grater or equal to 1, (Wi) belongs to A } + + Is A regular? If it is, give the formal definition of A (i.e., show what the + five-tuple definition of A is). 4.(20%) Transfer the DFA in Figure 1.14 of the textbook to a GNFA and then obtain a regular expression. Please remove q1 first, q2 second, and then q0. We give Figure 1.14 here ( Σ={0,1,2,r} ): → 0↑↓ ┌─┐ │q1│ ↙└─┘↖ ↙ ↗ ↘ ↖ 2,r ↙ ↗ ↘ ↖2 ↙ ↗1 1 ↘ ↖ ↙ ↗ ↘ ↖ ╔═╗ 2 ┌─┐ →║q0║→→→→→→→→→│q2│ ╚═╝←←←←←←←←←└─┘ ↓↑ 1,r ↓↑ → → 0,r 0 5.(20%) Assume Σ={0,1}. Consider the language ψ (empty set). (a) Give a DFA to recognize the language ψ. Show the transition diagram and the formal five-tuple definition. We require you to use the smallest possible number of states. For example, if a 4-state DFA and a 3-state DFA can both recognize this language, then you should not consider the 4-state one. (b) Transfer your DFA to GNFA and then get a regular expression (of course this regular expression should be ψ). -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 61.229.220.150 ※ 編輯: pinkyenyen 來自: 61.229.231.102 (10/18 10:01)