(1) (10%),
(a) calcium chloride, CaCl2,
(b) sulfur dioxide, SO2,
(c) cobalt(II) chloride hexahydrate, CoCl2o6H2O,
(d) dinitrogen pentoxide, N2O5,
(e) ozone, O3,
(f) chloric acid, HClO3,
(g) magnesium perchlorate, Mg(ClO4)2,
(h) iron(III) nitrate, Fe(NO3)3.
(2) (20%),
(a) H3O+, hydronium ion,
(b) NH4NO3, ammonium nitrate, (c) PI3,phosphorus triiodide,
(d) CuO, copper(II) oxide or cupric oxide,
(e) CrCl3,chromium trichloride,
(f) HNO3, nitric acid,
(g) NO, nitrogen monoxide,
(h)HCl, hydrochloric acid or hydrogen chloride,
(i) CaCO3, calcium carbonate,
(j) NaHCO3, sodium hydrogen carbonate,
(k) KCN, potassium cyanide,
(l) CH4, methane,
(m) AgBr, silver bromide,
(n) PbO2 lead (IV) oxide,
(o) KMnO4,potassium permanganate,
(p) Mg(OH)2 magnesium hydroxide,
(q) H2S, hydrogen sulfide,
(r) CuSO4, copper sulfate,
(s) AgNO3 silver nitrate,
(t) element-114, uuq or ununquadium.
(3) (10%),
(a) cyclopropane, [(CH2)3],
(b) pentane, CH3-CH2-CH2-CH2-CH3
(c) methylamine, CH3NH2,
(d) acetic acid, CH3COOH,
(e) ethanol, CH3CH2OH
(f) acetone, CH3COCH3,
(g) 3-methyl-1-butanol, CH3-CH2(CH3)-CH2-CH2OH
(h) difluoromethane, CH2F2,
(i) cyclohexanol, [c-C6H12OH],
(j) benzene, C6H6.
(4)
chromatography [see Figure 1-4, page 7 of textbook] + 補充教材(10%)
(5) (8%),
(a) 2 NO + O2 → 2 NO2,
(b) 2 C2H6 + 7 O2 → 4 CO + 6 H2O,
(c) Ag2SO4(aq) + BaI2(aq) → BaSO4(s) + 2 AgI(s),
(d) CO + 2 H2 → CH3OH
(at 350℃ and 340 atm, with ZnO and Cr2O3 as catalysts)
(6) (3%)
5 SO32-(aq) + 2 MnO4-(aq) + 6 H+(aq) → 5 SO42-(aq) + 2 Mn2+(aq) + 3H2O(l)
(7)
3 CN-(aq) + 2 MnO4-(aq) + H2O(l) → 2 MnO2(s) + 3 OCN-(aq) + 2OH-(aq)
(3%)
(8)
Cl2 + 2 NaClO2 → 2 ClO2 + NaCl, 1 gallon of 2.0M of NaClO2 =>
2.0(3.785) = 7.6 moles, this will produce 7.6(0.97) = 7.4 moles of ClO2 (分子
量為35.5+2x16.0=67.5), 67.5x7.4 = 500 g = 5.0 x 10(2) g (6%)
(9) (6%)
(a) (150.0/342)/250.0 = 1.75 M,
(b) [98.3(0.979)/60.0]/5.00= 0.321 M,
(c) [125(0.792)/32.00]/15.0 = 0.206 M
(10)
補充教材 (10%)
(11)
(a) m = Vd = 600 x 0.998 = 599 g;
(599/18.02) x 6.022 x 1023 = 2.00 x 1025 water molecules (4%)
(b) n = (1.00 x 0.600) / (0.08206 x 293) = 2.50 x 10-2 mol;
2.50 x 10-2 x 6.022 x 1023 = 1.50 x 1022 gas molecules. (4%)
(c) v = (3 x 8.314 x 293/29.3)1/2 = 499 m/s (4%)
(12)
(a) PCO = cCOPtot = (4.0 x 102 / 106 ) x 750 torr = 0.30 torr [2%]
(b) nCO/V = PCO/RT = CO molecules per m3 of air [4%]
(13)
(a) (H2O)4H+ [2%] (b) (H3O+)(H2O)3 [2%] (c) 4 [2%]
嗯，就降啦，加油吧
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