※ [本文轉錄自 NTUAC93 看板]
作者: jack7521 (認真打好每一球) 看板: NTUAC93
標題: [答案]化學期中考古題答案
時間: Tue Nov 9 20:41:32 2004
(1) (10%),
(a) calcium chloride, CaCl2,
(b) sulfur dioxide, SO2,
(c) cobalt(II) chloride hexahydrate, CoCl2o6H2O,
(d) dinitrogen pentoxide, N2O5,
(e) ozone, O3,
(f) chloric acid, HClO3,
(g) magnesium perchlorate, Mg(ClO4)2,
(h) iron(III) nitrate, Fe(NO3)3.
(2) (20%),
(a) H3O+, hydronium ion,
(b) NH4NO3, ammonium nitrate, (c) PI3,phosphorus triiodide,
(d) CuO, copper(II) oxide or cupric oxide,
(e) CrCl3,chromium trichloride,
----> 這邊應該是 chromium chloride, 不是 trichloride
(f) HNO3, nitric acid,
(g) NO, nitrogen monoxide,
(h)HCl, hydrochloric acid or hydrogen chloride,
(i) CaCO3, calcium carbonate,
(j) NaHCO3, sodium hydrogen carbonate,
(k) KCN, potassium cyanide,
(l) CH4, methane,
(m) AgBr, silver bromide,
(n) PbO2 lead (IV) oxide,
(o) KMnO4,potassium permanganate,
(p) Mg(OH)2 magnesium hydroxide,
(q) H2S, hydrogen sulfide,
(r) CuSO4, copper sulfate,
(s) AgNO3 silver nitrate,
(t) element-114, uuq or ununquadium.
(3) (10%),
(a) cyclopropane, [(CH2)3],
----> 這個 C3H6 應該會比較好畫
(b) pentane, CH3-CH2-CH2-CH2-CH3
(c) methylamine, CH3NH2,
(d) acetic acid, CH3COOH,
(e) ethanol, CH3CH2OH
(f) acetone, CH3COCH3,
(g) 3-methyl-1-butanol, CH3-CH2(CH3)-CH2-CH2OH
CH3
|
----> 應該是..CH3-CH-CH2-CH2-OH
(h) difluoromethane, CH2F2,
(i) cyclohexanol, [c-C6H12OH],
----> 這應該是 C6H11OH
(j) benzene, C6H6.
(4)
chromatography [see Figure 1-4, page 7 of textbook] + 補充教材(10%)
(5) (8%),
(a) 2 NO + O2 → 2 NO2,
(b) 2 C2H6 + 7 O2 → 4 CO + 6 H2O,
(c) Ag2SO4(aq) + BaI2(aq) → BaSO4(s) + 2 AgI(s),
(d) CO + 2 H2 → CH3OH
(at 350℃ and 340 atm, with ZnO and Cr2O3 as catalysts)
(6) (3%)
5 SO32-(aq) + 2 MnO4-(aq) + 6 H+(aq) → 5 SO42-(aq) + 2 Mn2+(aq) + 3H2O(l)
(7)
3 CN-(aq) + 2 MnO4-(aq) + H2O(l) → 2 MnO2(s) + 3 OCN-(aq) + 2OH-(aq)
(3%)
(8)
Cl2 + 2 NaClO2 → 2 ClO2 + NaCl, 1 gallon of 2.0M of NaClO2 =>
2.0(3.785) = 7.6 moles, this will produce 7.6(0.97) = 7.4 moles of ClO2 (分子
量為35.5+2x16.0=67.5), 67.5x7.4 = 500 g = 5.0 x 10(2) g (6%)
(9) (6%)
(a) (150.0/342)/250.0 = 1.75 M,
(b) [98.3(0.979)/60.0]/5.00= 0.321 M,
(c) [125(0.792)/32.00]/15.0 = 0.206 M
(10)
補充教材 (10%)
(11)
(a) m = Vd = 600 x 0.998 = 599 g;
(599/18.02) x 6.022 x 1023 = 2.00 x 1025 water molecules (4%)
(b) n = (1.00 x 0.600) / (0.08206 x 293) = 2.50 x 10-2 mol;
2.50 x 10-2 x 6.022 x 1023 = 1.50 x 1022 gas molecules. (4%)
(c) v = (3 x 8.314 x 293/29.3)1/2 = 499 m/s (4%)
(12)
(a) PCO = cCOPtot = (4.0 x 102 / 106 ) x 750 torr = 0.30 torr [2%]
(b) nCO/V = PCO/RT = CO molecules per m3 of air [4%]
(13)
(a) (H2O)4H+ [2%] (b) (H3O+)(H2O)3 [2%] (c) 4 [2%]
嗯，就降啦，加油吧
--
※ 發信站: 批踢踢實業坊(ptt.cc)
◆ From: 140.112.239.46
--
3 自然就是美 傾聽‧自然之美 [ltlmouse]
14 NB_NATURE 悠在 Σ 自 然 美 >擁抱自然，舒適且美妙 [joannie]
16 JChang 自然 ◎J.小豪的心情筆記版 jman208
--
※ 發信站: 批踢踢實業坊(ptt.cc)
◆ From: 140.112.239.119
※ 編輯: Jman208 來自: 140.112.239.119 (11/10 03:48)
※ 編輯: Jman208 來自: 140.112.239.119 (11/10 06:14)
※ 編輯: Jman208 來自: 140.112.239.119 (11/10 06:23)