※ 引述《wadelin (阿德 N )》之銘言：
: 作業6中
: 助教給ㄉ答案中
: 第六題ㄉb
這題主要的意思是說
這個module是不適用
需要考慮相對論
而解答中只是粗略的算
L = rmRv = nh(bar) where r = 1/(1- square of B)1/2 ,B =v/c & R is redius
KZq2/R2 = mv2/R
=> (1+B2/2)B = Z/137
^^^^
From this term we can see there is some error overhere.
:& 第七題ㄉb
delta X : root mean square of X
delta Px : root mean square of Px
delta Ee = delta Px2/2Me
where Me is the mass of electron
delta En = delta Px2/2Mn
where Mn is the mass of neutron
and Mn = 1837*Me
so delta En = Ee/1837
#supplement:
What's the physics of this problem7 ?？
First point :
delta Ee > nuclear energy levels
Show the electron is unstable in nucleus.
Second point:
delta En < nuclear energy levels
Show the neutron is stable in nucleus.
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