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推 killernest:有些其實可以不用乘開的 ㄎㄎ 10/25 00:23
我佛心來著，其實是想賺P幣
發一發離散第一章的解答
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1.1 & 1.2
(8+6)x(4+6+2)
9(a) =168
[(8+6)x(4x3)]x[6x(6x3)]
(b) =18144
[8x(6x3)]x[6x(1x3)]x[(8+6)x(4x3)]
(c) =73156608
8!/3!
20(a) =6720
6!
(b) =720
12!/(4!3!2!3!)
23 =27720
(2+1+7)!/(2!7!)
27(a) =360
(7+1+2)!/(7!2!)
(b) =360
請見原文書的解答
(c) 請見原文書的解答
12x1+6x2+8x3
28(a) =48
和規則
(b) 和規則
12x6x8
29(a) =576
積規則
(b) 積規則
2^10
33(a) =1024
3^10
(b) =59049 注意：此題中文本翻譯有誤
8!/4
36(a) =10080
(b) =我忘了算
(16C10)x(10!/10)x(6!/6)
37 =348713164800
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1.3
6+(6C2)+(6C3)+(6C4)+(6C5)+1=2^6-1
4(a) =63
6C3
(b) =20
(6C2)+(6C4)+1
(c) =31
(13C5)x4
8(a) =5148
48C1
(b) =48
13x(48C1)
(c) =624
(4C3)x(4C2)
(d) =24
(4C3)x(4C2)x13
(e) =312
(4C3)x13x(4C2)x12
(f) =3744
(4C3)x13x(48C2)
(g) =58656
(13C2)x(4C2)^2x(44C1)
(h) =123552
15C2
15(a) =105
25C3
(b) =2300
=2300
25C4
=126500
8C3
20(a) =56
8C4
(b) =70
忘了算
(c) =忘了算
nC3
21(a) =(nC3)
2邊 1邊
(b) =(nC3)-n-n(n-4) , 其中 n>=4
4!/2!
25(a) =12
4!/2!
(b) =12
-2x(4!/2!)
(c) =-24
-2x9x(4!/2!)
(d) =-216
8x3x4x[8!/(3!2!2!)]
(e) =161280
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1.4
35C32
7(a) =6545
31C28
(b) =4495
11C8
(c) =165
1
(d) =1
43C40
(e) =12341
(31C28)-(6C3)
(f) =4475
(8C6)x(34C31)
18(a) =167552
(5C3)x(34C31)
(b) =59840
23C4
19 =8855
證明略
22 證明
證明略
23(a) 證明
證明略
(b) 證明
有錯請在回文中提醒，才能訂正
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