看板 NTUEE107HW 關於我們 聯絡資訊
※ 引述《yaochia (錄影中˙請微笑)》之銘言: : 這兩個子題.. : 怎麼處理多變數啊... (a) f(0)=0 since let y=0 f(x)=f(x)+f(0)+0+0 => f(0)=0 (b) f'(0)=lim(x->0)((f(x)-f(0))/(x-0)) =lim(x->0)(f(x)/x)=1 (c) (f(x+y)-f(x))/y = x^2 + xy + f(y)/y y->0 LHS = f'(x) = x^2 + 0 + f'(0) = x^2 + 1 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.112.239.182
yaochia:了.. 推 140.112.115.2 10/05
JGU:(大驚) 函數方程?! 推 140.112.7.59 10/05
kafai:就是函數方程La 推140.112.239.182 10/05
yaochia:解釋一下.. 推 140.112.115.2 10/05
kafai:想我解釋甚麼呢? 推140.112.239.182 10/05
yaochia:函數方程 推 140.112.115.2 10/05
JGU:函數方程...據說是比微分方程還難的東西.. 推 61.230.43.243 10/05