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問一題非線性的差分方程..... Xt+1=aXt(1-Xt) for 0<a<4 ,X=0 is an equilibrium.Besides,there is another equilibrium. (a)For 1<a<4,determine whether 0 is a stable equilibrium X* (b)For 1<a<4,caculate the non-zero equilibrium X* (c)For 1<a<3,determine whether the equilibrium X* is stable (d)For 3<a<4,determine whether the equilibrium X* is stable -- http://photolink.com.tw/ouyang0716 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 203.68.107.82