[請益] php錯誤訊息

[ondiet (ondiet)]

我是利用書上的範例

mysql_num_rows(): supplied argument is not a valid MySQL result resource in
C:\AppServ\www\test\db_func.php on line 3
去找了這個地方只有如下

function db_num_rows($res)      {return mysql_num_rows($res);}

不知道？要怎麼解決才好


<?php
        include("db_conn.php");
        include("db_func.php");

        // 查詢註冊帳號名稱是否包含不雅字詞資料 BEGIN
        $SQLStr = "SELECT * FROM bad_words WHERE b_words LIKE '%$username%'";
        $res = db_query($SQLStr);
        // 查詢註冊帳號名稱是否包含不雅字詞資料 END

        if (db_num_rows($res)>0) // 若查詢資料有相符
        {
                echo "<script>";
                echo "alert(\"請勿使用不雅名稱" . $username . "為帳號\");";
                echo "location.href = \"registry1.php\";";
                echo "</script>";
        }
?>
檔案一開始include db_func.php
但是卻卡在mysql_num_rows(): supplied argument is not a valid MySQL result resource in
C:\AppServ\www\test\db_func.php on line 3

還有一開始就include 那$res的參數是什麼
謝謝

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推 shadowjohn  :'%$username%' 改成　'%{$username}%' 試試