Re: 嗚

[aakid (象棋)]

※ 引述《aakid (象棋)》之銘言：
: 好哇.................(開始後悔高中化學都不碰了，嗚嗚，連個基礎都沒有)
: 先一兩題好了
: *. A buffer solution contains 0.1M CH3-COOH and 0.1M sodium acetate (that
: is, it is a 0.2M acetate buffer). Calculate the pH after addition of 4ml of
: 0.025N HCl to 10ml of the buffer. The pKa for acetic acid is 4.74 .
:                                                           Answer:  pH=4.65
: 我自己是這樣想的：
:             CH3-COOH + NaCl <=======> CH3-COO-Na + HCl
:         pH = pKa + log  CH3-COO-Na 
:                          CH3-COOH
:      ==> pH = 4.74 +log  CH3-COO-Na 
:                           CH3-COOH
:                              然後就卡了，算出來跟老師給的答案不一樣...TT
這一題解出來了
mole加加減減.........XD
--
┌┌┌┌ Origin: 小魚的紫色花園 <fpg.twbbs.org> 140.112.200.214 ───┐┐┐┐
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標題: Re: 嗚
時間: Sun Oct 19 22:28:35 2003

※ 引述《aakid (象棋)》之銘言：
: 好哇.................(開始後悔高中化學都不碰了，嗚嗚，連個基礎都沒有)
: 先一兩題好了
: *. A buffer solution contains 0.1M CH3-COOH and 0.1M sodium acetate (that
: is, it is a 0.2M acetate buffer). Calculate the pH after addition of 4ml of
: 0.025N HCl to 10ml of the buffer. The pKa for acetic acid is 4.74 .
:                                                           Answer:  pH=4.65
: 我自己是這樣想的：
:             CH3-COOH + NaCl <=======> CH3-COO-Na + HCl
:         pH = pKa + log  CH3-COO-Na 
:                          CH3-COOH
:      ==> pH = 4.74 +log  CH3-COO-Na 
:                           CH3-COOH
:                              然後就卡了，算出來跟老師給的答案不一樣...TT
這一題解出來了
mole加加減減.........XD
--
┌┌┌┌ Origin: 小魚的紫色花園 <fpg.twbbs.org> 140.112.200.214 ───┐┐┐┐