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A 65kg bungee jumper leaps from a bridge. She is tied to a bungee cord that is 12 m long when unstretched, and falls a total of 31m . Calculate the spring constant k of the bungee cord assuming Hooke's law applies. 我ㄉ解法是 (31-12)/65*g這樣錯了嗎??答案不是這個耶......幫我解釋一下?? -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.123.222.193
SmArTyau:用能量守衡去算吧? mgh+0+0=0+(1/2)kx^2+0 11/04 00:30
SmArTyau:k=2mgh/x^2=2*65*g*31/19^2=11.16g 11/04 00:32
chenkaihsu:the answer is not 11.16..@@ 11/04 13:10
tatty:他後面還有個g耶........你確定你有看清楚嗎? 11/05 00:01
chenkaihsu:sorry iam wrong.....我沒看到gggg 11/05 00:13