原文：
A measurement establishes the position of a proton with an accuracy of
+-10^(-11)m. Find the uncertainty in the proton's position 1s later.
Assume the velocity of the proton is much less than the light velocity
in vacuum.
不太懂那一秒過後是什麼意思，原來想說用delta(P)>=h(bar)/delta(X)
再用delta(P)算得delta(E)，然後再用一次測不準原理得到delta(t)。
但是好像跟題目的要求不太符合，還是說直接另delta(t)=1s 去反推最後的
delta(X)呢?，請高手幫忙一下，感謝。
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