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A point sruce s (波長 = 500nm) is placed 1m from an aperture consisting of a hole of 1-mm radius in there is a circular opaque obstacle whose radius is 1/2mm. The receiving point P is 1m from the aperture. What is the irradiance at P compared to the irradiance if the aperture were removed. 這題是 Fresnel diffraction ?? 只知道 I = Up ^ 2 ,L= [(R1)^2]/波長 等效焦距L是1m ? 其實不太懂這題如何起手 謝謝 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 114.37.75.236