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Find the conditional probability that there are at least three kings in the hand givin that the hand contains at least two kings. 我的想法: C1=at least three kings C2=at least two kings P(C1ㄇC2) P(C2) P(C1│C2)= ────── = ──── = 1? P(C2) P(C2) 請問我哪裡觀念錯了@@" -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 218.166.103.160
dh3014:P(C1 and C2) 是 P(C1)吧? 10/28 13:13
nono1987113:喔喔!對耶P(C2)的範圍比P(C1)來的大~謝謝DH大 10/28 15:30