Sorry for the wrong correction about this question.
I thought another story about this question yesterday.
Actually, the type of player 1 and player 2 does not have
to be independent.
You can calculate the conditional probability from
the disjoint distribution matrix, and get the results
which I derived yesterday.
TA Jack
※ 引述《Jackliu2619 ()》之銘言：
: I found that the disjoint distribution matrix does not have enough information
: for you to calculate the expected payoffs for each player under different
: situations. Therefore, I have to add some description of the question:
: (1) Assume the type of player 1 and player 2 are independent
: (2) Player 1 is type 1 with the probability 0.5
: Player 2 is type 1 with the probability 0.4
: Then you can check the answer by yourselves.
: TA Jack
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