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※ 引述《stonycindy (Esperanza)》之銘言: : Question:An automobile repair shop makes an initial estimate X(in thousands) : need to fix a car after an accident. Say X has the p.d.f. : f(x)=2e^[-2(x-0.2)] 0.2<x<∞. : Given X=x, the final payment Y has a uniform distribution between : x-0.1 and x+0.1. What is the expected value of Y? : 麻煩請寫計算過程! : 謝謝! : Answer:E(Y)= x and E(x)=700 令z=x-0.2 , 0<z<∞ f(z)=2e^(-2z) , 0<z<∞ , 所以Z是指數分配 E(Z)=1/2=0.5 E(X)=E(Z)+0.5=0.7 in thousands=700 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 220.131.227.32