看板 Statistics 關於我們 聯絡資訊
※Example Let Y_n (or Y for simplicity) be b(n,p). Thus Y is approximately N(p,p(1-p)/n). Statisticians often look for functions of statistics whose variances do not depend upon the parameter. Here the variance of Y/n depends upon p. Can we find a function, say u(Y/n), whose variance is essentially free of p? Since Y/n converges in probability to p, we can approximate u(Y/n) by the first two terms of its Taylor's expansion about p, namely by u(Y/n) ≒ v(Y/n) = u(p) + (Y/n - p)u'(p). Of course, v(Y/n) is a linear function of Y/n and thus also has an approximate normal distribution; clearly, it has mean u(p) and variance [u'(p)]^2.p(1-p)/n. (這是Δ-method的應用 ) But it is the latter that we want to be essentially free of p; thus we set it equal to a constant, obtaining the differential equation u'(p) = c/√p(1-p). A solution of this is u(p) = (2c)arcsin√p. If we take c = 1/2, we have, since u(Y/n) is approximately equal to v(Y/n), that u(Y/n) = arcsin√(Y/n) has an approximate normal distribution with mean arcsin√p and variance 1/4n, which is free of p. --------------------------------------------------------------------------- Why do statisticians often look for functions of statistics whose variances do not depend upon the parameter? 這個Example裡,u(Y/n), whose variance is essentially free of p 有什麼用途? P 還有,不太懂為什麼要 Y/n -----> p,才能用泰勒展開式展開u(Y/n)? Δ-method的主要應用就是做上述這些事嗎? -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 203.64.26.246