NTU 86 (c)
六. The voltaic cell, Pb(s)|Pb2+, Na2SO4(0.1M), PbSO4(s)||Sn+(1M)|Sn(s),
generates a voltage of 0.19V. The standard reduction potentials for
Pb+ and Sn+ are -0.13V and -0.14V, respectively.
(a)What is the concentration of Pb2+ in the anode compartment?
(b)Calculate the Ksp for PbSO4
我的算法如下：
可推論 Pb2+ + Sn => Pb + Sn2+ Eo=0.01
[Sn2+]
0.19 = 0.01- (0.0592/2)*log────, [Sn2+]=1M 代入
[Pb2+]
可是不知道對不對耶
因為算出來的[Pb2+]很大 約10^6
不合 PbSO4 的Ksp 1.3*10^(-8)
希望高手指點一下
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