※ 引述《cheyu (....)》之銘言：
: 1. ln【A】= -3.344 【A】=?
A=exp-3.344 直接取exp不就好了
還是說不能用計算機?@@
: 2. A certain reaction has an activation energy of 54.0 KJ/mole.
: As the temperature is increased from22℃ to a higher temperature,
: the constant increases by a factor of 7.00. Calculate the higher
: temperature.
k1=Aexp(-54000/295R)
k2=Aexp(-54000/RT) A=constant 又k2/k1=7
兩個一除,T就出來了
: 3. Ea for the uncatalyzed reaction O3(g)+O(g)迳2O2
: Is 14.0 KJ.Ea for the same reaction when catalyzed is 11.9kJ.
: what is the ratio of the rate constant for the catalyzed reaction to
: that for the uncatalyzed reaction at 25℃? Assume that the frequency
: factor A is the same for each reaction.
剛上面用的方法是一模一樣的 只是求的東西不同
k1=Aexp(-14000/RT)
k2=Aexp(-11900/RT) R跟T都已知
相除就可以算出k1/k2了
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