A 10.0g chunk of sodium metal (Na) is dropped into a mixture of 50.0g of water
and 50.0g of ice at 0'C. The reaction is as follows:
2Na(s)+ 2H2O(l)-->2NaOH(aq)+H2(g) △H=-368KJ
The △H(fus) of ice is 6.0 kj/mole. Assuming that the final mixture has a
heat capacity of 4.18J/g'c, calculate the final temperature.
麻煩高手囉
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