if the initial rate for the second-order reaction:2A→B is 1.0*10^-6 MS^-1
for [A]0= 0.01M at 25度C
a) what is the concentration of B after 10 minutes?
(已求出速率常數=0.01 半生期為10^8 s)
b) if the activation energy is 40KJmol^-1, what will be the initial rate
for the same reaction?(gas constant R=8.134JK^-1mol^-1)
這題我是這樣算的: 因為知道上升十度C速率加快兩倍 所以上升25度=加快4√2倍
所以溫度上升後的初速率變成(1.0*10^-6)*4√2= 5.657*10^-6
不曉得我這樣算對不對??請大大幫忙解答謝謝!!!!
--
※ 發信站: 批踢踢實業坊(ptt.cc)
◆ From: 118.168.68.250