[化學] 一題普化(波函數)

[yuseke (大將)]

痾這是一題台大的期中考題

我只會做a跟= ="

能不能請前輩告訴我後面三題該怎麼處理(不用給我步驟...)

就是幫我解釋一下這樣就好  謝謝....




For a hydrogen atom in its ground state, the wavefunction is:

            1  ╭  1 ╮^3/2
    Ψls = ──│──│     e^(-r/a0),     a0 = 5.29 ×10^-11 m
           √π╰ a0 ╯

    Calculate the relative probability of finding the electron in the area
    described. Assuming the probability of a sphere of volume is identical.

(a) in a sphere of volume 1.0 ×10^-3 pm^3 centered at nucleus.
(b) in a sphere of volume 1.0 ×10^-3 pm^3 centered on a point
    1.0 ×10^-11 m from the nucleus.
(c) in a sphere of volume 1.0 ×10^-3 pm^3 centered on a point 53 pm from
    the nucleus.
(d) in a shell between two concentric spheres, one with rarius 9.95 pm and the
    other with radius 10.05 pm.
(e) in a shell between two concentric spheres, one with rarius 52.85 pm and the
    other with radius 52.95 pm.

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推 sparkle0829:這公式沒學過QQ~後醫板問應該會比較快有人可以解?
→ confused7749:這根本就Zumdahl第12章第135題 公式根本不是問題所在
→ biup2:Ψ 看到就投降了
→ confused7749:樓上幾篇有zumdahl詳解 找第12章的詳解就有了
→ yuseke:謝謝  我會去找的
→ fs83:台大越來越變態...
→ yuseke:其實有很多更難的 = =
→ yuseke:有的老師普化在上物化跟群論的書裡頭的東西
→ fs83:原PO是說現在台大的普化課程嗎?
推 sparkle0829:我看到就認輸了阿XD
→ yuseke:是阿
→ yuseke:我是回樓樓上
推 l17:很簡單啊(逃
推 sparkle0829:原Po還不快快站內信confused大大 看怎麼解
→ confused7749:不是吧 我覺得原po解得出來耶 就機率密度x體積 波函
→ confused7749:數平方就是機率密度呀 而且平方後公式就更簡單了 再
→ confused7749:根據所求代入適當r值 體積也不難求呀 況且zumdahl詳
→ confused7749:寫得詳細多了 題目很straightforward 沒轉什麼彎 你
→ confused7749:們也太快認輸了吧
→ mimipig:太快認輸XDDDD
→ fs83:原PO是上哪個系的普化?
→ yuseke:心理系
→ fs83:囧"
推 rubidus:別這麼快投降阿  機率就│Ψ│^2    都是代入就可算
→ rubidus:Max Born   → Born interpretation