※ 引述《darkhero (嘿嚇～～HERO)》之銘言：
: ※ 引述《chen0404 (這個冬天會很暖)》之銘言：
: : A computer desinger designs a new computer that has 60 instructions in the
: : machine language and the maximal addresable memory
: : space is 512 MB .
: : (a)how many bits will be used in the instruction register to hold a
: : two-address instruction?
: : (b)what will be the decoder's input and output size used for IR(op)?
: : 想了很久...請問一下要如何解阿...感恩!!
: a.60 instruction=6 bits , 512MB=2^29=29 bits so 29*2+6=64 bits
: 2^5<60<2^6....所以6bits, hold a two-address 所以要29*2 (我理解的@@")
這裡的 hold a two-address 指的是指令格式可以支援"兩個"operand(運算元)
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