看板 TransCSI 關於我們 聯絡資訊
拜託板友幫我算一下囉 一直都搞不太懂的一題... 題目大意是看的懂,但是還是不會算 Consider a single-surface disk drive having the following tracteristics. Number of track per disk : 60 Number of sectors per track : 20 Bits per second transfer rate : 500,000 Revolutions per minute rotational speed : 360 Assume that byte is 8 bits How many bytes is the nominal storage capacity of one disk? (If no gaps or special formatting is assumed) 可不可以教一下這是要怎樣計算? 還有答案 麻煩了~謝謝! -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 61.31.178.50
forris:題目要問磁碟容量有多大,跟轉速,位元傳輸速率無關 01/04 00:51
forris:題目也沒說硬碟裡有幾片磁碟,假設算一片,60*20*1=1200 byte 01/04 00:52